24x^2-4x-48=0

Solution for 24x^2-4x-48=0 equation:

24x^2-4x-48=0

a = 24; b = -4; c = -48;
Δ = b2-4ac
Δ = -42-4·24·(-48)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-68}{2*24}=\frac{-64}{48}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+68}{2*24}=\frac{72}{48}
=1+1/2
$